The location where a variable is declared affects the location from where the variable can be accessed. This accessibility or visibility of variables inside a program is known as scope.
\nA variable declared outside of a function is known as a global variable. A global variable has global scope and therefore can be accessed from anywhere in the program. Consider the following:
\nconst name = "Hemanta" // name is a global variable\n\nfunction greeting() {\n console.log(`Hello ${name}`)\n}\n\nfunction myName() {\n console.log(`My name is ${name}`)\n}\n\ngreeting() // Hello Hemanta\n\nmyName() // My name is Hemanta\n\nconsole.log(name) // HemantaHere, the name variable is declared outside of the greeting() & myName() function. Therefore it is a global variable and can be accessed within both the functions.
The word block simply refers to the code inside the curly braces of a function. A variable declared inside a function is a local variable and can only be accessed by the code within the function block. Consider the following:
function greet() {\n const name = "Hemanta" // name is a local variable created by greet\n console.log(`Hello ${name}`)\n}\n\ngreet() // Hello Hemanta\n\nconsole.log(name) // Reference error: name is not definedconsole.log(name) throws a reference error because name is a local variable, which is accessible only within the greet() function block (the code inside the curly braces) where it is defined. The name variable is erased from memory after execution of the greet() function.
Lexical scoping refers to how variables names are resolved when functions are nested. Consider the following:
\nfunction greet() {\n const name = "Hemanta"\n function greetMe() {\n console.log(`Hello ${name}. Nice to meet you.`)\n }\n greetMe()\n}\ngreet() // Hello Hemanta. Nice to meet you.greet() function creates a local variable called name and a function called greetMe(). greetMe() is a nested function inside greet() function body. Note that the greetMe() function has no local variables of its own. Because nested functions have access to the variables declared in the outer scope, greetMe() function can access the name variable declared in the greet() function.
Let’s consider another example:
\nconst firstName = "Hemanta"\n\nfunction greet() {\n const lastName = "Sundaray"\n function greetMe() {\n console.log(`Hello ${firstName} ${lastName}`)\n }\n greetMe()\n}\n\ngreet() // Hello Hemanta SundarayAbove, firstName is a global variable because it is declared outside of the greet() function. During the execution of the greet() function, JavaScript doesn’t find the firstName variable inside the greetMe() function scope. Therefore, it goes up the scope chain and looks for the variable in the outer scope of the greetMe() function. The outer scope of the greetMe() function is the greet() function scope. Javascript doesn’t find the firstName variable even there. JavaScript again goes up the scope chain and looks for the variable in the outer scope of the greet() function. The outer scope of the greet() function is the global scope, where JavaScript finds the variable. This is how JavaScript looks up in the scope chain to resolve variable names.
Now, we know that inner functions have access to the variables declared in the outer function. However, outer functions don't have access to the variables declared inside inner functions.
\nConsider the following example:
\nconst firstName = "Hemanta"\n\nfunction greet() {\n const lastName = "Sundaray"\n function greetMe() {\n const title = "Mr"\n console.log(`Hello ${firstName} ${lastName}`)\n }\n greetMe()\n console.log(`Hello ${title} ${lastName}`)\n}\n\ngreet() // Hello Hemanta Sundaray\n\n// ReferenceError: title is not definedconsole.log(`Hello ${title} ${lastName}`) returns a reference error because greet() function tried to access the title variable declared inside greetMe() function (which is nested inside the greet() function), and we know that an outer function does not have access to the variables defined within its nested function.
function greet() {\n const name = "Hemanta"\n function greetMe() {\n console.log(`Hello ${name}. Nice to meet you.`)\n }\n // Note that greetMe() function is not executed below.(No parentheses after the name of the function)\n return greetMe\n}\n\ngreet()() // Hello Hemanta. Nice to meet you.In JavaScript, a function can return another function. (A function that returns another function is called a higher-order function.) In the example above, the greet() function returns the greetMe() function. It is very important to note that the greetMe() function is only returned, not executed (no parentheses after the name of the function).
Next, you may ask why are there double pair of parentheses in greet()(); on the last line? Shouldn't there be only one pair of parentheses like greet()?
Let me explain. greet()(with single pair of parentheses) will execute the greet() function. The execution of the greet() function returns the greetMe() function. Note that the greet() function only returns the greetMe() function. greetMe() function has not been executed yet. Therefore, we need to add another pair of parentheses after greet() in order to execute the greetMe() function.
By the way, you can also write the above code snippet in the following way:
\nfunction greet() {\n const name = "Hemanta"\n function greetMe() {\n console.log(`Hello ${name}. Nice to meet you.`)\n }\n return greetMe\n}\n\nconst result = greet()\n\nresult() // Hello Hemanta. Nice to meet you.Here, we have saved the return value of greet() function in a variable. And then we add parentheses and semicolon after the name of the variable to execute the retuned value(which is the greetMe() function in our case.).
We also know that when a function finishes its execution, the local variables are erased from memory. They remain no longer available for use. So, it is reasonable to expect that when we execute the greet() function, the name variable ceases to exist. Therefore, when we execute greetMe() function (which is returned by the greet() function) by adding another pair of parentheses after greet(), we should get an error. Because greetMe() function requires the name variable which is no longer available for use.
Yet, the code above executes without any error. How come? This is where the concept of closure comes into picture.
\nThe concept of closure says that a function maintains reference to variables that were within scope during the declaration of the function.
\nFrom mozilla.org:
\n\n\nA \"closure\" is the combination of a function and the lexical environment within which that function was declared. This environment consists of any local variables that were in-scope at the time the closure was created.
\n
We know that inner functions have access to the variables declared in the outer scope. Therefore, greetMe() function maintains reference to the name variable even after the execution of the greet() function and therefore executes without any error.
Scope pollution occurs when you have too many variables in the global scope or when you reuse variables across different scopes. Let's understand the concept using an example:
\nlet name = "Hemanta"\n\nfunction greet() {\n name = "Theo"\n console.log(name)\n}\n\ngreet() // Theo\n\nconsole.log(name) // TheoInside the greet() function block, we forgot the word let before the name variable. As a result, we accidentally assigned a new name to the name variable present in the global scope instead of declaring a new name variable. This is the reason why console.log(name) returned Theo instead of Hemanta.
As you can see, reusing variables across different scopes can result in unexpected code output. Therefore, you must exercise caution and follow the best practice.
\nIt is best practice not to define variables in the global scope. Always scope your variables as tightly as possible using block scope. This will help you easily keep track of variables. Also, your code will remain modular, more understandable and easier to maintain.
\nhttps://developer.mozilla.org/en-US/docs/Web/JavaScript/Closures
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